Question

Find the surface area of the "unrolled" cylinder where a = 4 cm and b = 8 cm.Leave your answer in terms of t.

Answer 1

Answer:

The surface area of the cylinder is:

`96\pi`

Step-by-step explanation:

The surface area of the cylinder is:

`\begin{gathered} 2\pi r^2+2\pi rh \\ =2\pi(4^2)+2\pi(4)(8) \\ =32\pi+64\pi \\ =96\pi \end{gathered}`

Where r is the radius and h is the height