Question

Solve x2 + 4x + 3 = 0 by completing the square.1) -6, –12) -3, –13) 1,34)-6, –2

Answer 1

`\begin{gathered} x^2+4x+3=0 \\ (x+3)\cdot(x+1)=0 \\ x_1=-3 \\ x_2=-1 \end{gathered}`