Question

A rectangle is 7 times as long as it is wide. The perimeter is 32 feet. Find the dimensions.The length isfeet where the width isfeet.

Answer 1

Let l and w be the length and width of the rectangle, respectively.

Therefore, according to the question,

`\begin{gathered} l=7w \\ and \\ P=32 \\ P=2l+2w \end{gathered}`

Therefore, solving for l and w,

`\begin{gathered} l=7w \\ 2(l+w)=32 \\ \Rightarrow l=7w,l+w=16 \\ \Rightarrow7w+w=16 \\ \Rightarrow w=2 \\ and \\ \Rightarrow l=7*2=14 \end{gathered}`

The answer is length=14ft, width=2ft