Question

What is the angle of refraction if a ray that makes an angle of 35.0° with the normal in Quartz (n=1.46) travels to Water (n=1.33)?

Answer 1

Using Snell's law we can write

`n_1\sin\theta_1=\text{ n}_2\sin\theta_2;`

Here

`\begin{gathered} n_1=\text{ refractive index of incident medium= 1.46;} \\ n_2=\text{ refractive index of refracting medium = 1.33} \\ \theta_1=\text{ angle of incident= 35}\degree; \\ \theta_2=\text{ angle of refraction} \end{gathered}`

S0 according to problem

`\begin{gathered} 1.46\sin35\degree\text{ = 1.33}\sin\theta_2; \\ sin\theta_2=\text{ }(1.46*0.57638)/(1.33)\begin{cases}sin35={0.57638} \\ \end{cases} \\ sin\theta_2=0.6327; \\ \theta_{2=\text{ }}\sin^(-1)(0.6327); \end{gathered}`

Final answer is

`\sin^(-1)(0.6327)`