Question

Find the 9th term of the geometric sequence whose common ratio is 1/3 and whose first term is 6.

Answer 1

Given: the geometric sequence whose common ratio is 1/3 and whose first term is 6.

Find: 9th term of the geometric sequence

Explanation:

`\begin{gathered} a_n=a_1(r)^(n-1) \\ a_9=6((1)/(3))^(9-1) \\ a_9=6((1)/(3))^8 \end{gathered}`

Final answer: the required answer is

`(6)/(3^8)`