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Translate Pre Image coordinates left 6 units and down 15 units

Translate Pre Image coordinates left 6 units and down 15 units-example-1
asked
User Zae
by
8.7k points

1 Answer

4 votes

Given:

There are three coordinated given as


\begin{gathered} A(8,17) \\ B(8,11) \\ C(2,11) \end{gathered}

Required:

Translate pre image coordinate left 6 unites and down 15 unites and find the post image coordinates

Explnation:

First of all

if image translate left or right means traslate in x axis we have to mchange x coordinates

if image translate up or down means translate in y axis we have to change y coordinates

now if translate left we subtract the translated unis or if translate righ we add translated unists

similarly

if translate down we subtract the translated unis or if translate up we add translated units

Here image translate left for 6 units means translate in x axis and subtract because translate left


\begin{gathered} A1(8-6,17)=(2,17) \\ B1(8-6,11)=(2,11) \\ C1(2-6,11)=(-4,11) \end{gathered}

now image translate dow for 15 units means translate in y axis and subsract because translate down


\begin{gathered} A^(\prime)(2,17-15)=(2,2) \\ B^(\prime)(2,11-15)=(2,-4) \\ C^(\prime)(-4,11-15)=(-4,-4) \end{gathered}

Final answer:

Post image coordinates are


\begin{gathered} A^(\prime)(2,2) \\ B^(\prime)(2,-4) \\ C^(\prime)(-4,-4) \end{gathered}

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