Question

A battle droid is peeking out of a small window 10 feet above and 30 feetaway from Han At what angle must Han launch his blaster to destroy thebattle droid?Show your work here and explain how you arrive at your answer.

Answer 1

We will determine the angle as follows:

`\sin (\theta)=\frac{10}{\sqrt[]{10^2+30^2}}\Rightarrow\sin (\theta)=\frac{10}{10\sqrt[]{10}}\Rightarrow\sin (\theta)=\frac{1}{\sqrt[]{10}}`
`\Rightarrow\theta=\sin ^(-1)(\frac{1}{\sqrt[]{10}})\Rightarrow\theta=18.43394882`
`\Rightarrow\theta\approx18.5`

So, he must shot at an angle of approximately 18.5°.