Question

Find a solution of the quadratic equation.6x squared + 7x + 2 =0

Answer 1

Given the equation:

`6x^2+7x+2=0`

We will use the following rule to find the solution to the equation:

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

From the given equation: a = 6, b = 7, c = 2

So,

`\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=(-7\pm1)/(12) \\ x=(-7-1)/(12)=-(8)/(12)=-(2)/(3) \\ or,x=(-7+1)/(12)=-(6)/(12)=-(1)/(2) \end{gathered}`

So, the answer will be option B) x = -1/2, -2/3