Question

Let f (x) = x^3. What is the x-intercept of the graph of y= f (x-4) ?

Answer 1

Let f(x)=x^3

y=f(x-4) would be:

`y=(x-4)^3`

X-intercept would be, where y=0.

So, substitute y=0 and solve for x:

`\begin{gathered} 0=(x-4)^3 \\ 0=x-4 \\ x=4 \end{gathered}`

X-intercept would be (4, 0).