asked 136k views
1 vote
You need a 55% alcohol solution. On hand, you have a 150mL of a 45% alcohol mixture. You also have 80% alcohol mixture. How much of the 80% mixture will you need to add to obtain the desired solution?

asked
User Spekdrum
by
8.4k points

1 Answer

4 votes

Let the equired amount of 80% alcohol mixture required be 'x' mL.

If C represents the concentration and V represents the correspon

answered
User Pachanga
by
8.1k points
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