Question

Matthew found a deposit with a diameter that is 10^2 times as long as Josef’s. How many millimeters long is the diameter of Matthew’s deposit? Write your answer in standard form and with number names. Part C : Explain how you found your answer?

Answer 1

we have that

Josef’s sediment is 0.012 mm

Matthew’s deposit is 10^2 times as long as Josef’s

so

Matthew’s deposit=10^2*(0.012)=100*0.012=1.2 mm

therefore

The answer Part B is 1.2 mm

Part C

To obtain the answer to Part B, multiply the diameter of Josef’s sediment by the factor 10^2