Question

A medical practice group consists of seven doctors, 4 women and 3 men. The women are Drs. Jonswold, Hein, O'Conell, and Lee. The men are Drs. Penner, Paquette, and Marland. Supposenew patients are randomly assigned to one of the doctors in the group. Complete parts (a) through (d) below.

Answer 1

c) We have to find the probability that a new patient will be assigned to a male doctor.

In this case, we have 3 male doctors out of 7, so the probability can be expressed as 3/7.

We can find the probability as a percentage as:

`\begin{gathered} P(m)=(3)/(7)*100\% \\ P(m)=0.429*100\% \\ P(m)=42.9\% \end{gathered}`

Answer: c) the probability is 3/7 or, expressed as percentage, 42.9%.