Question

Can you please help me

Answer 1

first we will find the missing side with the pythagorean theorem:

`\begin{gathered} a^2+b^2=c^2 \\ a^2+4^2=5^2 \\ a^2+16=25 \\ a^2+16-16=25-16 \\ a^2=9 \\ a=\sqrt[]{9}=3 \end{gathered}`

for sin x

`\sin x=\frac{opposite}{\text{hypotenuse}}=(3)/(5)`

for cos x

`\cos x=(adjacent)/(hypotenuse)=(4)/(5)`

for tan x

`\tan x=(opposite)/(adjacent)=(3)/(4)`