Question

Hello! I am currently trying to answer this question. Could you provide the steps to help me solve it?

Answer 1

Given:

The length of the pipe is L.

The third harmonic has teh wavelength,

`(2L)/(3)`

To find:

The type of the pipe

Step-by-step explanation:

The wavelength of the harmonics for a pipe closed at one end is,

`\lambda=(4L)/(2n-1)`

The wavelength of the harmonics for a pipe open at both the ends is,

`\lambda=(2L)/(n)`

Here,

`n=1,\text{ 2, ......}`

The given wavelength is,

`(2L)/(3)`

which resembles the form,

`(2L)/(n)`

Hence, the pipe is open at the other end.