Question

The volume of a gas is 200 mL at 330.0 kPa what will the volume be when the pressure is reduced to 45.0 kPa assuming the temperature remains constant

Answer 1

V2 = 1466.7 mL

Step-by-step explanation

Given:

Volume 1 = 200 mL

Pressure 1 = 330.0 kPa

Pressure 2 = 45.0 kPa

Required: Volume 2

Solution:

To solve this problem we will use Boyles law

P1V1 = P2V2

V2 = P1V1/P2

V2 = (330.0 kPa x 200 mL)/45.0 kPa

V2 = 1466.7 mL