Question

A= 8 in, b= ? C= 14 in.using pythagorean theorem

Answer 1

by Pythagorean theorem'

`8^2+b^2=14^2`
`\begin{gathered} 64+b^2=196 \\ b^2=196-64 \end{gathered}`
`\begin{gathered} b^2=132 \\ b=\sqrt[]{132} \\ b=11.48 \end{gathered}`

b = 11.48