Question

Find the height of the trapezoidA=51CM2b=10cmb=7cmH?

Answer 1

`\begin{gathered} \text{Area of a trapezoid =}\frac{a\text{ +b}}{2}h \\ \end{gathered}`

we must find b one of the parallel sides before proceeding to find h

from the diagram b = 7cm

`\begin{gathered} \text{Area = }\frac{10\text{ +7}}{2}* h \\ 51\text{ = }(17)/(2)* h \end{gathered}`
`\begin{gathered} 51\text{ x 2 = 17h} \\ h\text{ =}(51*2)/(17) \\ h\text{ =6cm} \end{gathered}`