Question

Find the minimum value of the function f(x)=2x2-22x+68 to the nearest hundredth

Answer 1

Minimum value of the function

`f(x)=2x^2-22x+68`

To calculate the minimum value we will use the derivative.

`\begin{gathered} f^(\prime)(x)=4x-22 \\ 4x-22=0 \\ 4x=22 \\ x=(22)/(4) \\ x=5.5 \end{gathered}`

The answer would be 5.5