Question

3 Drag each equation to the correct location on the table. Determine the number of solutions to each equation. Then place each equation in the box that corresponds to its number of solutions. 35 = 2+ +1 2 – 1 = 45 + 3 31 – 2 35 + 1 2x + 3 = 35 – 1 1 2x + 1 = 21 No Solutions 1 Solution 2 Solutions Reset Next All rights reserved. i NE

Answer 1

`\begin{gathered} 3^x=2^x+1 \\ \text{Let x=1, then 3=2+1} \end{gathered}`

Then, it has just 1 solution, and it should be placed in the second column.

`\begin{gathered} 2^x-1=4^x+3. \\ \text{This has no solution} \end{gathered}`
`\begin{gathered} 3x-2=3^x+1 \\ \text{This has no solution.} \end{gathered}`

Next;

`\begin{gathered} (1)/(2)x+3=3^x-1 \\ \text{This has no solution. It should be in the first column} \end{gathered}`
`\begin{gathered} 2x+1=2^x \\ \text{Let x=0,} \\ 2(0)+1=2^0=1 \end{gathered}`

This has one solution, and it should be placed in the second column.