Question

Find the surface area of a right cone that has a radius of 9 inches and a height of 12 inches. Round your answer to the nearest hundredth. The surface area is about ⬜ square inches.

Answer 1

Answer:

The surface area of the right cone is:

`678.58in^2`

Step-by-step explanation:

The surface area of a right cone is:

`A=\pi r(r+\sqrt[]{r^2+h^2})`

Here, r = 9 in, and h = 12 in

so

`\begin{gathered} A=9\pi(9+\sqrt[]{9^2+12^2}) \\ \\ =9\pi(9+15) \\ =216\pi \\ =678.58in^2 \end{gathered}`