In AOPQ, 0 = 500 cm, p = 600 cm and q=380 cm. Find the measure of P to thenearest 10th of a degree.

Question

asked Sep 7, 2023 173k views

1 Answer

Weng · Answer 1 · 2023-09-12T09:10:17+0000

Answer: Triangle has three sides, which are:

$\begin{gathered} O=500\operatorname{cm} \\ P=600\operatorname{cm} \\ Q=380\operatorname{cm} \\ \end{gathered}$

We need to find the angle p, that is right across the side P:

$\angle A=\arccos ((b^2+c^2+a^2)/(2bc))=0.97895\text{rad}=56.09\text{degres}$

This is the value of angle A