Question

Dilate trianglesDraw the image of AABC under a dilation whose center is A and scale factor is

Answer 1

Since the dilation is centered at vertex A, the coordinates of A' are the same of A.

Then, to find the coordinates of B, let's multiply the distance AB by the scale factor:

`\begin{gathered} AB=12.6\\ \\ A^(\prime)B^(\prime)=12.6\cdot(1)/(4)=3.15 \end{gathered}`

Doing the same for AC, we have:

`A^(\prime)C^(\prime)=AC\cdot(1)/(4)=11.3\cdot(1)/(4)=2.825`

The points B' and C' are on the sides AB and AC, respectively.

Knowing this, let's draw the image A'B'C':

Since AB = BC, we also have A'B' = B'C' = 3.15.