Question

21 Mr. Bracken has 2 children that like to sit in trees. Jedi weighs 20kg and Phin weighs 25kg. The tallesttree in their yard is 20m high. The shortest branch is 10m high. If Jedi climbs to the highest branch andPhin climbs to the lowest brach, how much potential energy does each child have and which child has themost potential energy?A Jedi has 200 J, Phin has 500 J, therefore Jedi has the most potential energyB Jedi has 400 J, Phin has 250 J, therefore Phin has the most potential energy.c Jedi has 400 J, Phin has 250 J, therefore Jedi has the most potential energy.D Jedi has 200 J, Phin has 500 J, therefore Phin has the most potential energy.

Answer 1

Potential energy = mass x gravity x height

Where:

mass (kilograms)

gravity = 9.8 m/s2 =10 m/s2 (rounded)

Heigth = meters

Phin's potential energy = 25 kg x 10 m/s2 x 10m = 2500 J

Jedi's potential energy= 20kg x 10 m/s2 x 20 m= 4000 J

Comparing, 4000 (jedi)>2500 Phin

Jedi has the most potential energy.

Correct option : C