Question

Been looking for help for 2 hrs hopefully you can help

Answer 1

Given:

`\begin{gathered} \mu=19.9 \\ \sigma=33.1 \\ n=40 \end{gathered}`

To Determine:

`P(X>8.9)`

Solution

`\begin{gathered} P(X>z) \\ z=(x-\mu)/(\sigma)=(8.9-19.9)/(33.1)=(-11)/(33.1)=-0.3323 \end{gathered}`
`P(X>8.9)=1-P(X<8.9)=1-0.36982=0.63018`

Hence, P(x>8.9) = 0.6302 (nearest 4 d. p)