Question

What is the x intercepts or zeros for y = x^2 - 6x + 5

Answer 1

Given;

`y=x^2-6x+5`

The x-intercepts are the points where y=0.

Thus;

`x^2-6x+5=0`

Thus;

`\begin{gathered} x^2-x-5x+5=0 \\ \\ x(x-1)-5(x-1)=0 \\ \\ x-1=0,x-5=0 \\ \\ x=1,x=5 \end{gathered}`

ANSWER:

`x=1,x=5`