Question

Find the area of thisirregular figure.9 ft8 ft15 ft26 ft

Answer 1

The area of the irregular figure will be equal to the sum of area of triangle and the area of the rectangle.

The required area can be determined as,

`\begin{gathered} A=A_t+A_r \\ =((1)/(2)*8\text{ ft}*9\text{ ft)+(15 ft}*26\text{ ft)} \\ =36ft^2+390ft^2 \\ =426ft^2 \end{gathered}`

Thus, the required area of the irregular figure is 426 square feet.