Question

What is the equation of a line that is parallel to −2x+3y=−6 and passes through the point (−2, 0)?

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Answer 1

`y=(2)/(3)x +(4)/(3)`

Explanation:

`-2x+3y=-6\\3y=2x-6\\y=(2)/(3)x-2\\ \\\\Then\\y-0=(2)/(3)(x-(-2)\\ y-0=(2)/(3)x+(4)/(3) \\Therefore, the answer is y=(2)/(3)x+(4)/(3)`