Question

ABCD is a rectangle. Find angles a and b to the nearest degree

Answer 1

Given, ABCD is a rectangle AC is diagonal

Then AD=BC and AB=CD

And ∠ABC=∠BCA=∠CDA=∠DAB=90

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In ΔABC and ΔADC

∠ABC=∠ADC (Angle of rectangle)

AB=DC (Opposite side of rectangle )

AC=AC (Common side)

∴ΔABC≅ΔADC

∴∠ACD=∠ACB

∵∠ACD+∠ACB=90

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..........[Angle ACB is the angle of rectangle]

∴2∠ACD=90

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⇒∠ACD=45

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