Question

Find a if (10-a )×2 +(2a×2)+(4a+7)=48

Answer 1

First step: Simplify everything

`2(10-a) + 4a + 4a+7 = 48`

Next: Distribute required values

`20-2a+4a+4a+7=48`

Next: Time to add like terms

`6a = 21`

Final Step: Divide 6 on both sides to isolate variable

`a = (21)/(6)`

Thus, the value "a" =
`(21)/(6)`

Hope this helps :)