H(x) is given. h(x)=f(g(x)). Give a possible combination of f(x) and g(x). h(x)=(x-4)^3+(x-4)^(3)/(2) -1

Question

H(x) is given. h(x)=f(g(x)). Give a possible combination of f(x) and g(x).


`h(x)=(x-4)^3+(x-4)^(3)/(2) -1`

Answer 1

IN THEVPLACE OF x in the EQUATION OF f(x) we find that x-4 is plugged in..

THIS brings us to a result that g(x) is accompanied by x-4

`g(x) = x - 4`

and For f(x) it shows

`f(x) = {x}^(3) + {x}^{ (3)/(2) } - 1`

SINCE THE POSITION OF THE X VALUES OF WHICH x-4 was plugged in has to be reserved.

PLEASE IF YOU DON'T UNDERSTAND MESSAGE ME QUICKLY.