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imagine a game of three players where exactly one player winsin the end and all players have equal chances of being the winner. the game is repeated four times. find the probability that there is at least one person who wins no games

1 Answer

4 votes
(2/3) x (2/3) x (2/3) x (2/3) = 16/81 or 19.75%
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User Andrey Marchuk
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