Question

A man tries to break a metal box by throwing it off a building. If he throws straight down at 11.1

m/s and it hits the ground 3.9 seconds later, how tall was the building?
Round your answer to the nearest hundredth.

Answer 1

117 . 9 m

Step-by-step explanation:

df = do + vo t + 1/2 a t^2 df = final distance do =orig dist = 0

= 11.1 (3.9) + 1/2 (9.81)(3.9^2) = 117.9 m