Question

Solve each equation by factoring. Then solve the quadratic formula. (Show all work)

Answer 1

`- {k}^(2) + 3k = 28 - 2 {k}^(2) \\ - {k}^(2) + 2 {k}^(2) + 3k - 28 = 0 \\ {k}^(2) + 3k - 28 = 0 \\ (k + 7)(k - 4) = 0 \\ \\ k + 7 = 0 \\ \\ ork - 4 = 0 \\ \\ k = - 7 \\ \\ or \\ \\ k = 4`

ATTACHED IS THE SOLUTION

I GROUPED THE LIKE TERMS TOGETHER FIRST AFTER THAT THEN FACTORISED.