asked 158k views
2 votes
Find the differential dy in each of the followings:
y = 2t² +t+1

asked
User Rydwolf
by
8.2k points

1 Answer

3 votes

Answer:

4t + 1.

Explanation:

Use the General form of the differential:

If y = ax^n,

dy/dx = anx^(n-1)

So:-

y = 2t^2 + t + 1

dy.dt = 2*2t^(2-1) + t^(1-1) + 0

= 4t + 1.

answered
User Leeoniya
by
8.1k points
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