In ∆OPQ, q =18cm, o=96cm and

Question

asked Jan 7, 2023 171k views

1 Answer

Ekansh Rastogi · Answer 1 · 2023-01-11T18:53:45+0000

Given the information on the problem, we can use the law of cosines to find the length of p with the following equation:

$p^2=q^2+o^2-2q\cdot o\cdot\cos P$

substituting the values at hand, we get the following:

$\begin{gathered} p^2=(18)^2+(96)^2-2(18)(96)\cos 142 \\ \Rightarrow p^2=324+9216+2723.37 \\ \Rightarrow p^2=12263.37 \\ \Rightarrow p=\sqrt[]{12263.37}=110.74 \\ p=110.7\operatorname{cm} \end{gathered}$

therefore, the length of p is 111 cm

In ∆OPQ, q =18cm, o=96cm and

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Related questions

Categories

Other Questions