Question

A new airbus 5200 weighs 150,000 lbs and has a maximum take off acceleration of 2.7 m/s. How long of a runway is required to reach a velocity of 82 m/s for a safe take off.​

Answer 1

Answer: 1245.185m

I got this by taking the initial velocity of 0 the final velocity will be 82 and an acceleration of 2.7. I plugged these number into d=vf^2-vi^2 over 2 times acceleration then giving me the displacement or length of the runaway.