Question

X² - 6x - 41= 0 by completing squares

Answer 1

x = 3 ± 5
`√(2)`

Explanation:

x² - 6x - 41 = 0 ( add 41 to both sides )

x² - 6x = 41

to complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 3)x + 9 = 41 + 9

(x - 3)² = 50 ( take square root of both sides )

x - 3 = ±
`√(50)` = ± 5
`√(2)` ( add 3 to both sides )

x = 3 ± 5
`√(2)`