Question

Help find x-coordinate please

Answer 1

`\textit{vertex of a vertical parabola, using coefficients} \\\\ f(x)=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+6}x\stackrel{\stackrel{c}{\downarrow }}{+3} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 6}{2(1)}~~~~ ,~~~~ 3-\cfrac{ (6)^2}{4(1)}\right) \implies \left( - \cfrac{ 6 }{ 2 }~~,~~3 - \cfrac{ 36 }{ 4 } \right)\implies (\stackrel{x}{-3}~~,~~-6)`