Question

What is the energy of light whose wavelength is 4.06 x 10¹¹ m?​

Answer 1

The energy of light can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the light. By rearranging the equation and substituting the values, we can calculate the frequency and then use it to calculate the energy of the light.

Step-by-step explanation:

The energy of light can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 J·s), and f is the frequency of the light.

However, in order to use this formula, we need to know the frequency of the light. The wavelength of the light given in the question (4.06 x 10^11 m) can be used to determine the frequency using the equation c = λf, where c is the speed of light (3.00 x 10^8 m/s) and λ is the wavelength.

By rearranging the equation and substituting the values, we can calculate the frequency and then use it to calculate the energy of the light.

First, let's calculate the frequency:

f = c/λ = (3.00 x 10^8 m/s) / (4.06 x 10^11 m) ≈ 7.39 x 10^2 Hz

Now, we can calculate the energy:

E = hf = (6.63 x 10^-34 J·s)(7.39 x 10^2 Hz) ≈ 4.89 x 10^-31 J

Answer 2

`\quad \huge \quad \quad \boxed{ \tt \:Answer }`

`\qquad \tt \rightarrow \:{4.88 × 10}{-15} \:\: joules`

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`\large \tt Solution \: :`

By using Plank's equation ;

`\qquad \tt \rightarrow \: E = (hc)/( \lambda)`

`\qquad \tt \rightarrow \: E = \frac{6.6 * 10 {}^( - 34) \sdot3 * 10 {}^(8) }{ 4.06 * 10 {}^( - 11) }`

`\qquad \tt \rightarrow \: E = (19.8)/(4.06) * (10 {}^( - 26) * 10 {}^( 11 ) )`

`\qquad \tt \rightarrow \: E = 4.88 * 10 {}^( - 15) \: \: \: joules`

Answered by : ❝ AǫᴜᴀWɪᴢ ❞