asked 128k views
12 votes
Trisha had the following seven distances (in feet) in the triple jump.

29, 30, 28, 32, 28, 31, 27

What was the interquartile range of her distances?

1
2
5
3

asked
User Tereks
by
8.1k points

2 Answers

7 votes

Answer:

5

Explanation:

answered
User William Worley
by
7.8k points
11 votes

Answer:

5 is your answer sweetheart

Explanation:

We know that the range to a data set is the difference between the maximum data value and the minimum data value .

The given data set : 29, 30, 28, 32, 28, 31, 27

Maximum value = 32

Minimum value = 27

Then , the range the given data set would be :-

\begin{gathered}\text{Range = Maximum-Minimum}\\\\\Rightarrow\text{Range}=32-27=5\end{gathered}Range = Maximum-Minimum⇒Range=32−27=5

Hence, the range of her distances = 5

answered
User Eugen Halca
by
7.7k points
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