A 10-cm-long thin glass rod uniformly charged to 15.0 nC and a 10-cm-long thin plastic rod uniformly charged to - 15.0 nC are placed side by side, 4.30 cm apart. What are the el…

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asked Dec 10, 2023 79.3k views

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Ellene · Answer 1 · 2023-12-15T07:46:16+0000

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Answer: 354311 N/C, 275095 N/C, 458528 N/CExplanation:E = kQ/[r * √(r² + L/2)²], where L = 10 cm = 0.1 mE = kQ/[r * √(r² + 0.05²)]For the glass rod,E at 1 cm = E = k * 15*10^-9 / [0.01 * √…

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A 10-cm-long thin glass rod uniformly charged to 15.0 nC and a 10-cm-long thin plastic rod uniformly charged to - 15.0 nC are placed side by side, 4.30 cm apart. What are the el…

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