Question

6. (a) What minimum initial velocity must a projectile have to reach a target 90 km away? (b) What would the time of flight be?​

Answer 1

See below

Step-by-step explanation:

45 degree angle will produce the minimal velocity and maximum range...

Maximum range formula= v^2 / g

90 000 m = v^2 / 9.81 m/s^2

v = 939.6 m/s

Time would be calculated by using the horizontal component and the horizontal speed

90 000m / ( 939.6 m/s cos 45 m/s ) = 135.5 s