Question

(27/8)-^2/3??????????/

Answer 1

Answer: 4/9

Explanation:

`\displaystyle\\((27)/(8) )^{-(2)/(3)} =\\\\((3*3*3)/(2*2*2))^{-(2)/(3)}=\\\\ ((3^3)/(2^3) )^{-(2)/(3)} =\\\\(((3)/(2))^3)^{-(2)/(3) } =\\\\((3)/(2))^{-(3*2)/(3)} =\\\\((3)/(2))^(-2)=\\\\((2)/(3))^2 \\\\(2^2)/(3^2) =\\\\(4)/(9)`