Question

A line passes through the points (6​,​ -3)​ and (j,​ -4)​. If the slope of the line is 1/3 find the value of j​.

Answer 1

j = 3

Explanation:

Recall the slope formula:

`m=(y_(2)-y_(1) )/(x_(2)-x_(1) )`

Now, simply substitute the values from the question.

`(1)/(3) =(-4+3)/(j-6)`

Now, use the cross-multiplication method. (remember, when subtracting negatives, the negative becomes a positive)

`1(j-6)=3(-4+3)` Cross Multiplication

`1(j-6)=3(-1)` Simplify

`j-6=-3` Distributive Property

`j=3` Addition Property

Therefore, j = 3.