Question

Given that g'(x) = 4e^2x and g(1) = 0, Determine g(5)

Answer 1

Hello,

Explanation:

`g'(x)=4e^(2x)\\g(1)=0\\\\\displaystyle g(x)=\int\limits {4e^(2x)} \, dx =2e^(2x)+C\\\\g(1)=0=2e^2+C\\C=-2e^2\\\\g(x)=2e^(2x)-2e^2\\\\g(5)=2e^(10)-2e^2\approx{44038.154}`