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What is the equation of the parabola with focus (1, -3) and directrix y = 2? OA. y=-3x²+2x-2 OB. y=-4x²+8x-21 OC. Y=2/3x^2-4/3x+7/6. OD. Y=-1/10x^2+1/5x-3/5

What is the equation of the parabola with focus (1, -3) and directrix y = 2? OA. y=-3x²+2x-2 OB. y=-4x²+8x-21 OC. Y=2/3x^2-4/3x+7/6. OD. Y=-1/10x^2+1/5x-3/5
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What is the equation of the parabola with focus (1, -3) and directrix y = 2?

OA. y=-3x²+2x-2
OB. y=-4x²+8x-21
OC. Y=2/3x^2-4/3x+7/6. OD. Y=-1/10x^2+1/5x-3/5

asked
User Feihcsim
by
8.0k points

1 Answer

4 votes

Answer:

y = -x^2/10 + x/5 - 3/5

Explanation:

The answer is D: just rearrange

answered
User Paras Santoki
by
8.1k points
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