Question

ANSWER PLS!!!!!!!!!!!!!

Answer 1

`\huge \boxed{\sf A.A\ and\ B.7}\\\\\\\displaystyle \sf Adding\ all\ sides\ equaling\ to\ perimeter\\\\x+x+x+5=26\\\\3x+5=26 \\\\\\Solve\ for\ x \\\\Subtracting \ 5\ from\ both\ sides\\\\3x+5-5=26-5 \\\\3x=21 \\\\Dividing\ both\ sides\ by\ 3 \\\\(3x)/(3) =(21)/(3) \\\\x=7`

Answer 2

Part A: A, 3x + 5 = 26
Part B: X = 7