Question

9. The coefficient of static

friction between a 5kg block
and horizontal surface is 0.4.
What is the maximum
horizontal force that can be
applied to the block before it
slips?

Answer 1

19.6 Newtons

Step-by-step explanation:

`\displaystyle \textsf{The weight of the block is W= mg where m is the mass and g the acceleration due to gravity}`

`\sf W = 5kg, \; and\; g = 9.80 m/s^2`

`\sf W = 5 x 9.8 = 49\; Newtons`

`\textsf {If the coefficient of static friction is } $\mu_s$, the force to be applied for the block to slip is given by the equation}:\\\mathsf {f_s = \mu_s * W}\\\\\textsf {So force required, given $\mu_s$ = 0.4 is: }\\\\\\\mathsf {f_s = 0.4 * 49 = 19.6 } \textsf{ Newtons }`