Question

Solve the given equation. If necessary, round to four decimal places.

log3^0.1+ 2log3^x = log3^2 + log3^ 5

Answer 1

Answer: log3^0.1+\:2log3^x\:=\:log3^2\:+\:log3^{\:}5

Step-by-step explanation: go to symbolab.com to get the step by step explanation or to answer problems like this hope this helps.