Question

The common ratio of a sequence is 1/2. Two terms in the sequence are a5=1 and a8=1/8

what is the recursive formula?​

Answer 1

Since r = 1/2, and the fifth term = 1

1 = A×[(1/2)^(5-1)]

1 = A×[(1/2)^4]

1 = A× (1/16)

Explanation: